Just like my last recap on Saturday afternoon, the Braves let the opposition put up a highly lopsided number when Spencer Strider gave up 6 runs in the bottom of the 3rd in a scoreless game. (Am I troubled by Strider’s troubles? Not much.) Like Saturday night, the Braves immediately bounced back with not-quite-enough runs and continued to give up runs and continued to get not-quite-enough runs to catch up.

Unlike Saturday, though, the skies opened up in Pittsburgh which gave me time to answer a question: what is your probability of winning as a function of the maximum number of runs you’ve scored in any one inning? In other words, how important is a crooked number and how crooked does it need to be?

Here are the results:

Max Runs In An Inning By Either Team# of gamesWinning
12 or more771.0000

So if you want to be pretty damn sure you’re going to win a game, have a 12 run inning or more. But to the point of tonight’s game, a 6 run inning (so long as no one has a seven run inning or more) gives you a 92 percent chance of winning.

But once again some critical at-bats with men on (in a game in which the Braves outhit the Pirates 10-9) proved feckless. Feck. So Saturday was 8-6. This was 8-7. But it looked about the same, except for the precipitation.


A fairly rare 0-5 with an OBA of 0. RAJ only has 21 such days in his career. He remains at

August 7: 149 Hits, 25 HR, 53 SB

But there are still only four other players who have hit those three numbers in a season (Henderson twice, Morgan twice, Cedeno twice and Sandberg once.)